Chemistry, asked by muvvalaj, 7 months ago

at 313 kelvin temprature solubility of of salt is 37g. calculate the amount of solute dissolved in 65 grams of water at the same temprature. pls answer i will mark you brainliest. u will get 30 points if u answer this.

Answers

Answered by Jasleen0599
1

Correction: Solubility of salt is 37 gm per 100 gm.

Complete Answer:

Given:

Solubility of salt = 37 gm per 100 gm

Mass of water = 65 gm

To Find:

The amount of solute dissolved in 65 grams of water at the same temperature.

Calculation:

- According to the given condition:

The amount of salt dissolved in 100 gm of water = 37 gm

⇒ The amount of salt dissolved in 1 gm of water = 37/100

⇒ The amount of salt dissolved in 65 gm of water = (37/100) × 65

⇒ w = 24.05 gm

- So, the amount of solute dissolved in 65 grams of water is 24.05 grams.

Answered by hackeranshuman28
1

Answer:

Production of a Precipitate The mixing of two liquids may form a precipitate. A precipitate (pree SIP uh tayt) is a solid that forms from liquids during a chemical reaction.Let x/a = y/b = z/c = k, [By k method]

x = ak, y= bk and z=ck

L.H.S. = a3k3/a2 + b3k3/b2 + c3k3/c2 > k3[a + b + c]

R.H.S. = [ak + bk + ck]3/[a + b + c)2 → k3[a + b + c]3/[a + b + c)2

= k3(a + b + c)

L.H.S. = R.H.S. =

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Answer 4

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