At 380mm pressure and 0°C number of
moles of the gas present in 11.2 lit of it are
1) 0.25 2)0.5 3)0.75 4)1
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Hi,
Answer:
The number of moles of the gas present is 0.25 moles.
Explanation:
Given data:
The volume of the gas, V = 11.2 litre
Temperature, T = 0℃ = 273 K
Pressure, P = 380 mmHg = 380 / 760 atm = 0.5 atm …… [since 760 mmHg = 1 atm]
Ideal gas constant, R = 0.082057 L atm mol⁻¹ K⁻¹
To find: No. of mole of the gas present
Let the no. of moles of the gas be “n”.
Using the Ideal Gas Law,
PV = nRT
⇒ n = PV / RT
⇒ n = [0.5 * 11.2] / [0.082057 * 273] = 5.6 / 22.4 = 0.25 moles
Hope this helps!!!!!
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