Question

At 40 degrees celsius the vapour pressure in torr of methyl alcohol ethyl alcohol solution is represented by the equation p is equal to 1 19 x + 135 where x is the mole fraction of methyl alcohol then the value of limit x tends to 1 by x is

Answer 1

The methanol and ethanol torr is P = 119x + 135

Where x is the mole fraction of methyl alcohol, then the value of limit x tends to 1/x

P0−P/P0= X will be the mole fraction of solute.

If X=1, then vapor pressure of methanol P=P0

P=119(1)+135

⇒135+119=255torr

If X=0, then vapor pressure of methanol P=P0

P=119(0)+135

⇒P=135

Therefore the vapor pressure of pure ethanol is 135 torr.

Answer 2

Answer:

Explanation:

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