Question

At 40°c the vapour pressure of mixture of methyl alcohol and ethyl alcohol is represented by p=199x+135
(Where x is the mole fraction of methyl alcohol )
Wht are the vapour pressure of pure methyl alcohol and pure ethyl alcohol at 40°c

Answer 1

Answer:

The vapor pressure of pure methyl alcohol and pure ethyl alcohol at 40°C is 234 and 135 respectively.

Explanation:

Total pressure be given as p = 199x+135

Partial pressure of methyl alcohol =$p_{m}$

Partial pressure of ethyl alcohol =$p_{e}$

Mole fraction of methyl alcohol = x

Mole fraction of ethyl alcohol = y

x + y = 1

$p=p_m+p_e$

$p=\chi_mp^{o}_{m}+\chi_ep^{o}_{e}$

$p=xp^{o}_{m}+yp^{o}_{e}$

$p=xp^{o}_{m}+(1-x)p^{o}_{e}$

$p=xp^{o}_{m}+p^{o}_{e}-xp^{o}_{e}$

$p=x(p^{o}_{m}-p^{o}_{e})+p^{o}_{e}$

$99x+135=x(p^{o}_{m}-p^{o}_{e})+p^{o}_{e}$

comparing quantities:

$p^{o}_{e}=135$

$x(p^{o}_{m}-p^{o}_{e})=99x$

$p^{o}_{m}=99+p^{o}_{e}=99+135 =234$

The vapor pressure of pure methyl alcohol and pure ethyl alcohol at 40°C is 234 and 135 respectively.

Answer 2

Answer:

Explanation:

It's simple...

Just add 199+135

=334

Therefore,

Vapour pressure of pure methyl alcohol is 334

Vapour pressure of pure ethyl alcohol is 135

Hence 334 and 135 torr》》》》ans

☆☆☆☆☆☆☆☆☆☆☆☆☆☆☆