At 473 K, in the given equilibrium reaction what would be effect on Kc it temperature is increased
PCl5 (g) PCl3(g) + Cl2 (g) rH0 = 124.0 kJ mol–1
Answers
Answer:
PCl5 <=> PCl3 + Cl2;Kc = 8.3 × 10^-3
(a) Kc = [PCl3][Cl2]/[PCl5]
(b) if reaction will be reverse then , equilibrium constant ( K'c) = 1/Kc = 1/{8.3 × 10^-3}
= 120.48
(c) equilibrium constant is constant at constant temperature hence, there is no effect on Kc when addition of PCl5.
(c) equilibrium constant is independent upon concentration of pressure. Hence, Kc doesn't change with pressure.
(d) this is an endothermic reaction hence, when increases in the temperature Kf increases . So, Kc = Kf/Kb increases.
Answer:
When temperature is increased, the value of equilibrium constant is increased. The reaction is endothermic. When temperature is increased, Kf
is increased. Hence, Kc=Kf/Kr will also be increased
Mark it as the brainliest dear