Chemistry, asked by latahardik58, 2 months ago

At 473 K, in the given equilibrium reaction what would be effect on Kc it temperature is increased
PCl5 (g) PCl3(g) + Cl2 (g) rH0 = 124.0 kJ mol–1​

Answers

Answered by chpavithra
1

Answer:

PCl5 <=> PCl3 + Cl2;Kc = 8.3 × 10^-3

(a) Kc = [PCl3][Cl2]/[PCl5]

(b) if reaction will be reverse then , equilibrium constant ( K'c) = 1/Kc = 1/{8.3 × 10^-3}

= 120.48

(c) equilibrium constant is constant at constant temperature hence, there is no effect on Kc when addition of PCl5.

(c) equilibrium constant is independent upon concentration of pressure. Hence, Kc doesn't change with pressure.

(d) this is an endothermic reaction hence, when increases in the temperature Kf increases . So, Kc = Kf/Kb increases.

Answered by arya004patel
2

Answer:

When temperature is increased, the value of equilibrium constant is increased. The reaction is endothermic. When temperature is increased, Kf  

 is increased. Hence, Kc=Kf/Kr will also be increased

Mark it as the brainliest dear

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