Question

At 500 °C, hydrogen iodide decomposes according to

2HI(g)↽−−⇀H2(g)+I2(g)2HI(g)↽−−⇀H2(g)+I2(g)

For HI(g)HI(g) heated to 500 °C in a 1.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [H2]=0.326 M[H2]=0.326 M , [I2]=0.326 M[I2]=0.326 M , and [HI]=2.76 M[HI]=2.76 M . If an additional 1.00 mol of HI(g)HI(g) is introduced into the reaction vessel,

what are the equilibrium concentrations after the new equilibrium has been reached?

Answer 1

Answer:

At 500 °C, hydrogen iodide decomposes according to 2 HI ( g ) − ⇀ ↽ − H 2 ( g ) + I 2 ( g ) For HI ( g ) heated to 500 °C in a 1.00 L reaction vessel, chemical analysis determined these concentrations at equilibrium: [ H 2 ] = 0.335 M , [ I 2 ] = 0.335 M , and [ HI ] = 2.83 M .