At 500 k and 5 atmospheric pressure 12 moles of N2 combine with 15 moles of H2 and at equilibrium 6 moles of NH3 were formed. Calculate it's Kp
Answers
Answered by
0
Explanation:
N
2
(g)+3H
2
(g)⇌2NH
3
(g)
Since total volume is 1 L, the number of moles is equal to the molar concentration.
2 moles of N
2
are mixed with 6 moles of H
2
in closed vessel of one litre capacity.
If 50% N
2
is converted into NH
3
at equilibrium.
2×
100
50
=1 mole of N
2
will react with
3×1=3 moles of H
2
to form 2×1=2 moles of NH
3
2−1=1 mole of N
2
and 6−3=3 moles of H
2
will remain at equilibrium.
K
c
=
[N
2
][H
2
]
3
[NH
3
]
2
Answered by
0
Answer:
answer is 533
Explanation:
because if they combine with the h2 then the nh3 would be 553
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