Question

at 500°c the reaction between N2 and H2 to form ammonia has kc=6.0×10^2. what is the numerical value of kp for this raction ?​

Answer 1

Explanation:

N2 (g) + 3H2 (g) ---> 2NH3 (g)

$Kp = Kc \times {(RT)}^{n}$

$Kp = 6.0 \times {10}^{2} \times{ (8.314 \times 773)}^{ - 2}$

$Kp = \frac{ 6.0 \times {10}^{2} }{ {(8.314 \times 773)}^{2} }$

$Kp = 1.49 \times {10}^{ - 6}$