At 60% of its usual speed, a train of length L metres crosses platform 240 metres
long in 15 seconds. At its usual speed, the train crosses a pole in 6 seconds. What
is the value of L (in metres)?
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Answer:
Answer: Option D.
Let usual speed = S m/s.
According to the question,
60% of S= (L+240)/15
9S= L+240………… (i)
Also given that, S = L/6
L = 6S …. (ii)
From (i) & (ii)
9S= 6S+240
3S= 240
S=80 m/s
From (ii)
L= 6×80 =480
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