Chemistry, asked by vrajpatel982004, 3 months ago

At 600°C NH COONH2(s) + 2NH3(g) + CO2(g)
is Kp = 3.2 x 102 bar of equilibrium constant
;
So, calculate K. (R = 0.0831 L bar K-1 mol-1)

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At 600°C NH COONH2(s) + 2NH3(g) + CO2(g) is Kp = 3.2 x 102 bar of equilibrium constant ; So, calculate K. (R = 0.0831 L bar K-1 mol-1)

Answers

At 600°C NH COONH2(s) + 2NH3(g) + CO2(g)
is Kp = 3.2 x 102 bar of equilibrium constant
;
So, calculate K. (R = 0.0831 L bar K-1 mol-1)