Question

At 627∘C and one atm SO3 is partially dissociated into SO2 and O2.One litre of the equilibrium mixtureweighs 0.94 g under above conditions. Determine the partial pressure of the constituent gases in the mixture.

Answer 1

Answer:

$Given 2SO </p><p>3</p><p> </p><p> ⟷2SO </p><p>2</p><p> </p><p> +O </p><p>2</p><p>$

Explanation:

Weight of equilibrium mixture is 0.94g

Mol weight of equilibrium = sum of all molecules =176 g

We know that PV=nRT

0.3946 atm

Hence partial pressure of gases is 0.3946 atm