Math, asked by arpitanayak1883, 6 months ago

At 7:00 pm the temperature was 40F. If the temperature dropped steadily at a rate of 6 degrees per hour, what was the temperature at 11:00 pm? The answer with explanation please

Answers

Answered by Nerdyno1
4

Answer:

16F

Step-by-step explanation:

11-7=4

There were 6 degrees per hour falling and there were 4 hours.

Then it will be 6x4=24

Thus, 40-24= 16F

Answered by pulakmath007
3

The temperature at 11:00 pm is 16F

Given :

  • At 7:00 pm the temperature was 40F.

  • The temperature dropped steadily at a rate of 6 degrees per hour

To find :

The temperature at 11:00 pm

Solution :

Step 1 of 2 :

Calculate decrease in temperature

Here it is given that at 7:00 pm the temperature was 40F.

The temperature dropped steadily at a rate of 6 degrees per hour

Total time

= 11:00 pm - 7:00 pm

= 4 hours

∴ Total decrease in temperature

= 4 × 6 degrees

= 24 degrees

Step 2 of 2 :

Calculate the temperature at 11:00 pm

The temperature at 11:00 pm

= (40 - 24)F

= 16F

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