Question

At 700 K, the equilibrium constant KP
, for the reaction
2SO3
(g) 2SO2
(g) + O2
(g)
is 1.8 × 10–3 kPa. What is the numerical value of KC
for this reaction at the same temperature–

Answer 1

Hope it's helps you ........

Answer 2

Answer:

3.09 x 10 -7

Explanation:

Given: 2SO  

3

​  

⇌2SO  

2

​  

+O  

2

​  

 

1 atm=10  

5

 pa

Δn=n  

products

​  

−n  

reactants

​  

 

K  

p

​  

=1.8×10  

−3

KPa=1.8Pa=1.8×10  

−5

atm

T=700K

R=0.0821lit−atm

K  

p

​  

=K  

c

​  

(RT)  

Δn  

g

​  

 

 

K  

c

​  

=  

RT

K  

p

​  

 

​  

 

K  

c

​  

=  

700×0.0821

1.8×10  

−5

 

​  

=0.031×10  

−5

=3.1×10  

−7

 molL  

−1