Question

At 80° C, the vapour pressure of pure liquid ‘A’ is 520 mm Hg and that of pure liquid ‘B’ is 1000 mm Hg. If a mixture solution of ‘A’ and ‘B’ boils at 80° C and 1 atm pressure, the amount of ‘A’ in the mixture is (1 atm = 760 mm Hg)
(a) 52 mol percent
(b) 34 mol percent
(c) 48 mol percent
(d) 50 mol percent

Answer 1

Hello Friend

Option.C

Thank you

Answer 2

$\huge\mathfrak\pink{anSwEr}$

option C is correct

C) 48 mol % ✔️

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