Science, asked by rankers11, 4 months ago

At 800∘Kan reaction mixture continued 0.5 mole of SO2​,0.12 mole of O2​ and 5 mole of SO3​ at equilibrium. If the volume of the container is 1 lt. Calculate how much O2​ is to be added at this equilibrium in order to get 5.2 mole of SO3​ at the same temperature.​

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Answered by sangeetasathe8
0

Answer:

At 800 K a reaction mixture contained 0.5 mole of SO2 . 0.12 mole of O2 and 5 mole of SO3 at equilibrium. Kc for the equilibrium 2SO2 + O2 2SO3 is ...

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