Chemistry, asked by abmukthishjain20, 1 year ago


At 80°C, the vapour pressure of pure liquid A is 520 mm Hg and that of pure liquid B is 100mmHg. If
a mixture of solution A and B boils at 80°C and latm pressure. The amount of A in the mixture is
(1atm = 760mmHg)
1) 50 mol%
2) 52mol%
3) 34 mol%
4) 48 mol%

Answers

Answered by Anonymous
1
 <b>
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→ [B]


At 80°C, the vapour pressure of pure liquid A is 520 mm Hg and that of pure liquid B is 100mmHg. If
a mixture of solution A and B boils at 80°C and latm pressure. The amount of A in the mixture is
(1atm = 760mmHg)
1) 50 mol%
2) 52mol%
3) 34 mol%
4) 48 mol%

________________________________

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Answered by Anonymous
4

Answer :

At 80°C, the vapour pressure of pure liquid A is 520 mm Hg and that of pure liquid B is 100mmHg. If

a mixture of solution A and B boils at 80°C and latm pressure. The amount of A in the mixture is

(1atm = 760mmHg)

1) 50 mol%  

2) 52mol%

3) 34 mol%

4) 48 mol%

______________________

The correct option is (b):   52mol%

_________________________________

hope it helps :)

thanks :))

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