At 80°C, the vapour pressure of pure liquid A is 520 mm Hg and that of pure liquid B is 100mmHg. If
a mixture of solution A and B boils at 80°C and latm pressure. The amount of A in the mixture is
(1atm = 760mmHg)
1) 50 mol%
2) 52mol%
3) 34 mol%
4) 48 mol%
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Answered by
1
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At 80°C, the vapour pressure of pure liquid A is 520 mm Hg and that of pure liquid B is 100mmHg. If
a mixture of solution A and B boils at 80°C and latm pressure. The amount of A in the mixture is
(1atm = 760mmHg)
1) 50 mol%
2) 52mol%
3) 34 mol%
4) 48 mol%
________________________________
ᴴᴼᴾᴱ ᵀᴴᴱ ᴬᴺˢᵂᴱᴿ ᴴᴱᴸᴾ ᵞᴼᵁ !
Answered by
4
Answer :
At 80°C, the vapour pressure of pure liquid A is 520 mm Hg and that of pure liquid B is 100mmHg. If
a mixture of solution A and B boils at 80°C and latm pressure. The amount of A in the mixture is
(1atm = 760mmHg)
1) 50 mol%
2) 52mol%
3) 34 mol%
4) 48 mol%
______________________
The correct option is (b): 52mol%
_________________________________
hope it helps :)
thanks :))
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