Chemistry, asked by manojsrinivas70, 1 year ago

at 88 degreee benzene has a vapour preasure of900torr and toulene has a vapour pressure of 360 torr.what is mole fraction of benzene in the mixture with with the toulene will be boil at 88 degree c at 1atmospheric pressure , benzene toulene form an ideal solution.given that total =760 torr at 88 degree c

Answers

Answered by TheRose
52


To calculate the composition of this mixture at the given temperature, there is the requirement of the total pressure of the system.
One the total pressure of the system at the given temperature is known, one can apply the formula,
P=P(tolurne) + P(benzene)
= p0(toluene) * mole fraction (toluene) + p0(benzene) * mole fraction ( benzene)
take mole fraction of toluene as x and that for benzene
as 1-x and solve further to
Answered by himanshupassey26
10

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Answer: 0.740

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