Question

At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path.The bicyclist heading north is riding 6 km/hour faster than the bicyclist heading south. At 10:15, they are 42.5 km apart. Find the two bicyclists’ rates.

Answer 1

Answer:

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Step-by-step explanation:

let x=rate of bicyclist heading south

x+6=rate of bicyclist heading north

distance=travel time*rate

travel time=1 hr and 15 min=1.25 hr

1 .25x+1.25(x+6)=42.5

1.25x+1.25x+7.5=42.5

2.5x=35

x=14

x+6=20

rate of bicyclist heading south=14 km/hr

rate of bicyclist heading north=20 km/hr