Math, asked by skullsavagesai23, 8 months ago

At a bakery shop, a pastry costs ₹115.00 and a mix - veg wrap costs ₹150.00. Amrita
spent a total of ₹4100.00, buying x no. of pastries and y no. of mix - veg wraps.
Question 1: Which of the following equation represents the purchases made by
Amrita.
A) 150x + 115y = 4100
B) 23x + 30y = 850
C) 115x + 75y = 4100
D) 23x + 30y = 820
Question 2: If Amrita buys 20 pastries, how many mix - veg wraps did she buy?
Question 3: If Amrita wants to make a combo of pastry and mix – veg wrap, what is
the maximum number of combos she can make?

Answers

Answered by nikhilraman
1

Answer:

Answers below

Step-by-step explanation:

Q1.ans

150x + 115y = 4100(Because she is spending 4100 Rupees by buying combos of pastries and veg wraps that cost ₹115 and ₹150)

Q2.ans

20 Pastries= ₹2300

4100-2300= Remaining budget of ₹800

No. of Veg wraps=800/150=5 veg wraps

Q3.ans

115+150=265

No. of combos=4100/265=15

Amrita can make 15 combos

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