Math, asked by skullsavagesai23, 6 months ago

At a bakery shop, a pastry costs ₹115.00 and a mix - veg wrap costs ₹150.00. Amrita
spent a total of ₹4100.00, buying x no. of pastries and y no. of mix - veg wraps.
Question 1: Which of the following equation represents the purchases made by
Amrita.
A) 150x + 115y = 4100
B) 23x + 30y = 850
C) 115x + 75y = 4100
D) 23x + 30y = 820
Question 2: If Amrita buys 20 pastries, how many mix - veg wraps did she buy?
Question 3: If Amrita wants to make a combo of pastry and mix – veg wrap, what is
the maximum number of combos she can make?

Answers

Answered by priyanshu148831
1

1). A

2) 12 mix veg which price is 1800

3)

Answered by Rathijayachandran123
1

Answer:

I think 150x plus 115 y = 4100 represents her purchase

2) 12

EXPLANATION:

because the cost of one pastry is 150 and so the total rupees she spent for pastry will be 150 X number of pastry and same as in case of wraps

so total money will be sum of 150 x and 115 y

if she buys 20 pastry then cost of 20 pastry will be 20 *115

=2300

so the remaining money=4100 - 2300=1800

the number of wraps she can buy with 1800=1800/150=12

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