Math, asked by anshu1815, 3 months ago


At a banquet the ratio of the number of boys to the number of girls is 5:3. Halfway through the banquet 20 boys leave and the ratio becomes 5:4. How many girls are at the banquet?.​

Answers

Answered by aruanu1815
4

Answer:

Answer:

Given :-

At a banquet the ratio of the number of boys to the number of girls is 5:3.

Halfway through the banquet 20 boys leave and the ratio becomes 5:4.

To Find :-

How many girls are at the banquet.

Solution :-

Let, the numbers of boys be 5x

And, the number of girls be 3x

But in halfway through the banquet 20 boys leave and the ratio becomes 5:4.

According to the question,

\dfrac{5x - 20}{3x} = \dfrac{5}{4}

By doing cross multiplication we get,

⇒ 4(5x - 20) = 5(3x)

⇒ 20x - 80 = 15x

⇒ 20x - 15x = 80

⇒ 5x = 80

⇒ x = \sf\dfrac{\cancel{80}}{\cancel{5}}

➠ x = 16

Hence the required number of boys and girls are :

❐ Number of boys = 5x = 5(16) = 80

❐ Number of girls = 3x = 3(16) = 48

\therefore 48 girls are at the banquet.

Answered by Anonymous
45

Answer:

At a banquet the ratio of the number of boys to the number of girls is 5:3. Halfway through the banquet 20 boys leave and the ratio becomes 5:4. How many girls are at the banquet

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