At a blood donation camp organized to celebrate the World Diabetes Day, a total 270 volunteers had queued up for blood donation. The number of people with blood group ‘O’ was thrice the number with blood group A. The number of volunteers with blood group ‘AB’ was twice the number with blood group A and those with blood group B was 20 more than 4 times with blood group A. Find the number of volunteers of each blood group. What is your view on this act of donating blood.
Answers
Answer:
Given :
A right triangle ABC, right angled at B .
(i) AB = 10 cm. BC = 24 cm .
(ii) AB = 7 cm, BC = 24 cm .
To Find :
Length of AC .
Solution :
(i) AB = 10 cm. BC = 24 cm :
Using Pythagoras Theorem :
\longmapsto\tt{{(AC)}^{2}={(AB)}^{2}+{(BC)}^{2}}⟼(AC)
2
=(AB)
2
+(BC)
2
\longmapsto\tt{{(AC)}^{2}={(10)}^{2}+{(24)}^{2}}⟼(AC)
2
=(10)
2
+(24)
2
\longmapsto\tt{{AC}^{2}=100+576}⟼AC
2
=100+576
\longmapsto\tt{{AC}^{2}=676}⟼AC
2
=676
\longmapsto\tt{AC=\sqrt{676}}⟼AC=
676
\longmapsto\tt\bf{AC=26\:cm}⟼AC=26cm
(ii) AB = 7 cm, BC = 24 cm :
Using Pythagoras Theorem :
\longmapsto\tt{{(AC)}^{2}={(AB)}^{2}+{(BC)}^{2}}⟼(AC)
2
=(AB)
2
+(BC)
2
\longmapsto\tt{{(AC)}^{2}={(7)}^{2}+{(24)}^{2}}⟼(AC)
2
=(7)
2
+(24)
2
\longmapsto\tt{{AC}^{2}=49+576}⟼AC
2
=49+576
\longmapsto\tt{{AC}^{2}=625}⟼AC
2
=625
\longmapsto\tt{AC=\sqrt{625}}⟼AC=
625
\longmapsto\tt\bf{AC=25\:cm}⟼AC=25cm