Question

At a car park there are 100 vehicles, 60 of which are cars, 30 are vans and the remainder are lorries. If every vehicle is equally likely to leave, find the probability of:
a) van leaving first.
b) lorry leaving first.
c) car leaving second if either a lorry or van had left first

Answer 1

option c



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Answer 2

Answer:

Let S be the sample space of the experiment.

So, n(S) = 100

a). Now, let A be the event of van leaving first

⇒ n(A) = 30

So, Probability of van leaving first = P(A) = 30/100

                                                                       = 3/10

b). let B be the event of lorry leaving first

Now, Number of lorry in the car park = 100 - (60 + 30)

                                                              = 10

⇒ n(B) = 10

So, Probability of lorry leaving first = P(B) = 10/100

                                                                        = 1/10

c). If either a lorry or van had left first, then there would be 99 vehicles remaining, 60 of which are cars. Let T be the sample space and C be the event of a car leaving.

n(T) = 99  

n(C) = 60

Probability of a car leaving after a lorry or van has left = P(C) = 60/99

                                                                                                          = 20/33