At a carnival, food tickets cost $2 each and ride tickets cost $3 each. A total of $1,240 was collected at the carnival. The number of food tickets sold was 10 less than twice the number of ride tickets sold. The system of equations represents x, the number of food tickets sold, and y, the number of ride tickets sold. 2x + 3y = 1240 x = 2y – 10
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in the equation as we can say x= 2y-10.
so, substitute x=2y-10 everywhere then the x in 1240 gets cancelled with 2y-10 then solve the remaining you will get 4y-20+3y=1240
7y=1260
y=1260/7
y=180
then substitute the value of y everywhere
2x+3y=1240
2x+3(180)=1240
2x=1240-540
2x=700
x=350
DONE.
so, substitute x=2y-10 everywhere then the x in 1240 gets cancelled with 2y-10 then solve the remaining you will get 4y-20+3y=1240
7y=1260
y=1260/7
y=180
then substitute the value of y everywhere
2x+3y=1240
2x+3(180)=1240
2x=1240-540
2x=700
x=350
DONE.
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