Math, asked by raj05108888pbzzxi, 1 year ago

At a casino in Mumbai , there are three tables A, B and C . The payoffs at A is 20:1 , at B is 30:1 and C is 40:1 . If a man bets 200 at each table and wins at two of the tables , what can be the difference between the maximum and minimum earnings?

Answers

Answered by Anonymous
1


At a casino in mumbai, there are three tables A, B and C. The payoffs at A is 10:1, at B is 20:1 and at C is 30:1. If a man bets Rs 200 at each table and win at two of the tables, what is the maximum and minimum difference between his earnings can be?

A) Rs.2500B) Rs.2000C) Rs.4000D) None of these

Answer:   C) Rs.4000 

Explanation:

Maximum earning will be only when he will won on the maximum yielding table.

     A ----> 10:1

     B ----> 20:1

     C ----> 30:1

 i.e, he won on B and C but lost on A

 20 x 200 + 30 x 200 -1 x 200 = 9800

 minimum earning will be when he won on  table A and B and lose on that table 3.

Therefore, 10 x 200 + 20 x 200 - 1 x 200  =  6000-200 = 5800

Therefore, Difference= 9800 - 5800 = 4000

raj05108888pbzzxi: thnx a lot sir
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