Question

At a certain distance from a point charge (in C) the electric field is 200 V/m and the potential is 800 V. What is this distance

8 m

4 m

2 m

16 m​

Answer 1

Answer:

Distance, d = 6 m

Explanation:

Electric field due to a point charge, E = 500 V/m

Potential due to the point charge, V = 3000 V

The relation between the electric field and the electric potential is given by :

E=\dfrac{V}{d}E=

d

V

d is the distance.

d=\dfrac{V}{E}d=

E

V

d=\dfrac{3000\ V}{500\ V/m}d=

500 V/m

3000 V

d = 6 m

Hence, this is the required solution.

Answer 2

Answer:

4 m

Explanation:

Using the relation in E and V.

E = - dV/dr = - ∆V/∆r

Here,

E = 200 V/m

∆V = 800 V

Let the required distance be r.

=> 200 = 800/r

=> r = 800/200 m

=> r = 4 m

The required distance is 4 m.