Question

At a certain height a shell at rest explodes into two equal fragments. one of the fragments receives a

horizontal velocity 30m/s. The time interval after which, the velocity vectors will be inclined at 120degree

to

each other is

$(1) \sqrt{3}$
$(2)2\sqrt{3}$
$(3) 3 \sqrt{3}$
$(4) \sqrt{3} \div 2$





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Answer 1

At a certain height a shell at rest explodes into two equal fragments.

One fragment recieves a horizontal velocity of 30i^

the momentum of a system is conserved so the other fragment will move with same velocity but in opposite direction -30i^

vi^=30i^-10j^

vi^=- 30i^-10j^

For the complete and pls refer the attachment

I hope this helps