Question

At a certain height above the earth surface, the acceleration due to gravity is 4% of its value at the surface of earth. Determine the height

Answer 1

Answer:

4%ofg value is 4/100×9.8

=0.392

Explanation:

0.392=9.8×(r/r+h)^2

0.392/9.8=(r/r+h)^2

0.04=(r/r+h)^2

0.2=r/r+h

r+h=r/0.2

6.4×10^6+h=(6.4×10^6)/0.2

6.4×10^6+h=3.2×10^7

h=(3.2×10^7)_(6.4×10&6)

h=2.56×10^7

MEANS FROM EARTH SURFACE TO THE HEIGHT OF 2.56×10^7 g VALUE BECOMES 4% OF ITS ORIGINAL g VALUE