At a certain moment, in the reaction 2N2O5 4NO2 + O2; N2O5 is decomposing at the rate of 108 mg/L/s
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Answer:
56 M g /L S
Explanation:
2 N2O5 ---- 4 NO2 + O2
-1/2 [ d (N2O5 )/ dt ] = 1 /4 [d( NO2 ) /dt ]
therefore Rate of N2O5 is given 108 Mg/LS
Ans 1 /2 (108 ) = 56 Mg /LS
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