At a certain moment, the switch shown in
the figure is disconnected. The energy of the
oscillations immediately after the switch 'S' is
disconnected and at time 0.1 sec from the
time switch is disconnected are, respectively
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29 Q
10 uF
Answers
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Initial energy stored in capacitor 2 μF:U
i
=
2
1
2(V)
2
=V
2
Final voltage after switch 2 is on: V
f
=
C
1
+C
2
C
1
V
1
=
10
2V
=0.2 V
Final energy in both the capacitors, U
f
=
2
1
(C
1
+C
2
)V
f
2
=
2
1
×10×(
10
2V
)
2
=0.2 V
2
Therefore, energy dissipated =
V
2
V
2
−0.2V
2
×100=80%
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