Question

At a certain place, horizontal component is √3 times the vertical component. The angle of dip at this place is(a) 0(b) π/3(c) π/6(d) None of these

Answer 1

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Here is your answer

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BVBH = 3 where,Bv is the vertical component of earth's magnetic field. ... And we have,tan δ = BVBH = 3 BHBH = 3 tan δ =3 δ = 60° → (angle of dip) ... times the horizontal component. ... Given, straight B subscript straight V over straight B subscript straight H ... tan space straight delta space equals square root of 3

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Answer 2

Answer: The correct answer is 30 degree.

Explanation:

The expression for the angle of dip is as follows;

$\delta = tan^{-1}(\frac{V}{H})$

Here, V is the vertical component and H is the horizontal component.

It is given in the problem that at a certain place, horizontal component is √3 times the vertical component.

Put H= √3V in the above expression.

$\delta = tan^{-1}(\frac{V}{\sqrt{3}V})$

$\delta = tan^{-1}(\frac{1}{\sqrt{3}})$

$\delta = tan^{-1}(tan 30 degree)$

$\delta = 30 degree$

$\delta =\frac{\pi }{6}$

Therefore, the correct option is (c).