Physics, asked by wwwnarensankh1505, 1 year ago

At a certain place on earth, the horizontal component of earth's magnetic field is 3 times of its vertical component. The angle of dip at that place is

Answers

Answered by BhaveshMalviya
2

Horizontal and vertical components of Earth's magnetic field are equal at magnetic North and South poles. At these positions angle of dip will be 90° because direction of magnetic field of Earth is along the magnetic axis.Feb 25, 2018


BhaveshMalviya: please like
Answered by CarliReifsteck
3

Answer:

The angle of dip at that place is 60°.

Explanation:

Given that,

The ratio of vertical component and horizontal component of magnetic field  is

\dfrac{B_{v}}{B_{H}}=\sqrt{3}

Where, B_{v} is the vertical component of earth's magnetic field

B_{H} is the Horizontal component of earth's magnetic field

We need to calculate the angle of dip at that place

Using formula of angle

\tan\theta=\dfrac{B_{v}}{B_{H}}

Put the value of vertical and horizontal component of magnetic field

\tan\theta=\sqrt{3}

\theta=\tan^{-1}(\sqrt{3})

\theta= 60^{\circ}

Hence, The angle of dip at that place is 60°.

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