At a certain rate of compound interest, Rs 250 deposited on July 1, 2018 has to accumulate to
Rs 275 on January 1, 2019. Assuming the interest rate does not change and there are no
subsequent deposits, find the account balance on January 1, 2021.
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Answered by
6
Answer:
(Sec A + Cos A) (Sec A - Cos A)
We know that,
(a - b) (a + b) = a² - b²
Here,
a = Sec A
b = Cos A
Substituting,
Sec² A - Cos ² A
We know that,
1 + Tan² A = Sec² A
1 - Sin² A = Cos² A
Substituting,
1 + Tan² A - (1 - Sin² A)
1 + Tan² A - 1 + Sin² A
Tan² A + Sin² A
Therefore,
\boxed{\purple{\textsf{(Sec A + Cos A) (Sec A - Cos A) = Tan² A + Sin² A}}}
(Sec A + Cos A) (Sec A - Cos A) = Tan² A + Sin² A
Answered by
0
Answer:
At a certain rate of compound interest, Rs 250 deposited on July 1, 2018 has to accumulate to
Rs 275 on January 1, 2019. Assuming the interest rate does not change and there are no
subsequent deposits, find the account balance on January 1, 2021.
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