Question

At a certain rate of simple interest, a certain sum of money becomes double of itself in 10 years. in what time will it become triple of itself
​

Answer 1

Answer:

Since sum double itself in 10 years, so sum = S.I. for 10 years.

Since sum double itself in 10 years, so sum = S.I. for 10 years.Let sum =x. Then, S.I. =x and Time =10 years.

Since sum double itself in 10 years, so sum = S.I. for 10 years.Let sum =x. Then, S.I. =x and Time =10 years.∴Rate=(

Since sum double itself in 10 years, so sum = S.I. for 10 years.Let sum =x. Then, S.I. =x and Time =10 years.∴Rate=( x×10

Since sum double itself in 10 years, so sum = S.I. for 10 years.Let sum =x. Then, S.I. =x and Time =10 years.∴Rate=( x×10100×x

Since sum double itself in 10 years, so sum = S.I. for 10 years.Let sum =x. Then, S.I. =x and Time =10 years.∴Rate=( x×10100×x

Since sum double itself in 10 years, so sum = S.I. for 10 years.Let sum =x. Then, S.I. =x and Time =10 years.∴Rate=( x×10100×x )% =10%

Since sum double itself in 10 years, so sum = S.I. for 10 years.Let sum =x. Then, S.I. =x and Time =10 years.∴Rate=( x×10100×x )% =10%Now, sum =x, S.I. =2x, Rate =10%

Since sum double itself in 10 years, so sum = S.I. for 10 years.Let sum =x. Then, S.I. =x and Time =10 years.∴Rate=( x×10100×x )% =10%Now, sum =x, S.I. =2x, Rate =10%∴ Time =(

Since sum double itself in 10 years, so sum = S.I. for 10 years.Let sum =x. Then, S.I. =x and Time =10 years.∴Rate=( x×10100×x )% =10%Now, sum =x, S.I. =2x, Rate =10%∴ Time =( x×10

Since sum double itself in 10 years, so sum = S.I. for 10 years.Let sum =x. Then, S.I. =x and Time =10 years.∴Rate=( x×10100×x )% =10%Now, sum =x, S.I. =2x, Rate =10%∴ Time =( x×10100×2x

Since sum double itself in 10 years, so sum = S.I. for 10 years.Let sum =x. Then, S.I. =x and Time =10 years.∴Rate=( x×10100×x )% =10%Now, sum =x, S.I. =2x, Rate =10%∴ Time =( x×10100×2x

)years=20 years.