Math, asked by Mathsinventor, 6 months ago


At a certain rate of simple interest, rs 1600 becomes 2200 in 9/2 years. What sum of money
will become 5025 in 4 years and 9 months at the same rate of interest?

Answers

Answered by sheelaezhil
3

Answer:

Rs. 3600 will become Rs. 5025 in 4 years and 9 months at the same rate of interest.

Step-by-step explanation:

Given, principal = P = Rs. 1600

Amount = A = Rs. 2200

Simple interest = S.I = Rs.(2200 - 1600) = Rs. 600

Time = T = 4 \frac{1}{2} = \frac{9}{2}4

2

1

=

2

9

years

Rate = R

Now, Simple interest = S.I = \frac{PRT}{100}

100

PRT

=> 600 = \frac{1600\times R\times \frac{9}{2}}{100}

100

1600×R×

2

9

=> 600 = 72 R

=> R = \frac{600}{72}

72

600

= \frac{25}{3}%

3

25

%

Again, Amount = A = Rs. 5025

Principal = P

Time = T = 4 years 9 months = 4\frac{9}{12} = 4\frac{3}{4} = \frac{19}{4}4

12

9

=4

4

3

=

4

19

years

A = P + S.I

=> 5025 = P + \frac{PRT}{100}

100

PRT

=> 5025 = P + \frac{P\times \frac{25}{3}\times \frac{19}{4}}{100}

100

3

25

×

4

19

=> 5025 = P + \frac{19P}{48}

48

19P

=> 5025 = \frac{67P}{48}

48

67P

=> P = \frac{5025\times 48}{67}

67

5025×48

= Rs. 3600

Hence, Rs. 3600 will become Rs. 5025 in 4 years and 9 months at the same rate of interest.

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