Question

At a certain temperature and total pressure of 10 5 Pa, iodine vapour contains 40% by volume of I atoms Calculate K p for the equilibrium.

Answer 1

Partial pressure of I atoms= P1 = 40/ 100 x P total
= 40/100 x 10⁵
= 4 x 10⁴ Pa

Partial pressure of I₂ molecules,
PI₂ = 60/ 100 x P total
= 60/100 x 10⁵
= 6 x 10⁴ pa

now for the given reaction,
Kp = (pI)²/ PI₂

= (4 x 10⁴)² / 6 x 10⁴
= 2.67 x 10⁴ Pa

Answer 2

Answer:

Hi,

Here is the answer to your question:

 

Kp value at equilibrium for reaction,

I2 (g) ⇌2I (g)

is given as,

Given, 40% volume is occupied by I atoms.

∴ 60 % volume is occupied by I2.

Let V be total volume, then volume occupied by I and I2 are 0.4V and 0.6V respectively.

Partial pressure of I2 = (60/100) × 105 = 60 kPa

Partial pressure of I = (40/100) × 105 = 40 kPa

Substituting in equation for Kp,

Kp = = 2.67 × 104 KPa

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Explanation: