at a certain temperature and total pressure of 10 raise to power 5 p aiodine vapour contains 40% by volume of iodine atom
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Partial pressure of I atoms= P1 = 40/ 100 x P total
= 40/100 x 10⁵
= 4 x 10⁴ Pa
Partial pressure of I₂ molecules,
PI₂ = 60/ 100 x P total
= 60/100 x 10⁵
= 6 x 10⁴ pa
now for the given reaction,
Kp = (pI)²/ PI₂
= (4 x 10⁴)² / 6 x 10⁴
= 2.67 x 10⁴ Pa
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