At a certain temperature and total pressure of 10⁵Pa, iodine vapour contains 40% by volume of I atoms I₂ (g) ⇆ 2I (g) Calculate for the equilibrium.
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sorry I can't understand that what u have written in last line..plz ..clarify it to me....
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Partial pressure of 1 atoms = P1= 40/100 X P total ,
=40/100 x 105,
= 4x104 Pa.
partial pressure of I2 molecules,
PI2= 60/100 x105, 6x104 pa.
now you have to give reaction of Kp=( 4x104)2/ 6x 104= 2.67 x104 Pa .
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