Question

At a certain temperature the half life periodsfor catalytic decomposition of nh3. What will be the pressure when the half life period is 2.5 hours

Answer 1

Answer:

(t  

1/2

​

)  

1

​

 

​

=(  

a  

1

​

 

a  

2

​

 

​

)  

n−1

   where, n is order of reaction

From the given data,

1.92

3.52

​

=(  

6667

13333

​

)  

n−1

         (a∝ initial pressure)

         =(2)  

n−1

 

log  

1.92

3.52

​

=(n−1)log2=0.3010×(n−1)

0.2632=0.3010×(n−1)

n=1.87≈2

Similar calculations are made between first and third observations, n comes equal to 1.908 (≈2).

Thus, the reaction is of second order.

Explanation: