at a certain time a tree 6 m height cast a shadow of length 8 metres at the same time up all cast a shadow of length 20 m find the height of the Pole
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15 m.
When shadow length = 8 m then height of tree = 6 m
Therefore when shadow length = 20 m let height of pole = x.
(Hypotenuse remains the same as it’s measured at the same time.)
Hence, 6*20=8*x
Therefore, x = 15m.
When shadow length = 8 m then height of tree = 6 m
Therefore when shadow length = 20 m let height of pole = x.
(Hypotenuse remains the same as it’s measured at the same time.)
Hence, 6*20=8*x
Therefore, x = 15m.
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Height of pole is 15m
by taking the angle constant and equating tanx of both the equation we can find the height of the pole
plz mark it as the brainliest
by taking the angle constant and equating tanx of both the equation we can find the height of the pole
plz mark it as the brainliest
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