at a certain time a tree 6m high casts a shadow of length 8 meter. at same time a pole casts a shadow of length 20 m.find length of shadow
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let angle be @(instead of theta)
so,tan @=6\8=3/4
so we have got the ratio...
Compare it with second situation...
3\4=20/x
so x=26.6666666
so height is 26.67 m.(.approx)
so,tan @=6\8=3/4
so we have got the ratio...
Compare it with second situation...
3\4=20/x
so x=26.6666666
so height is 26.67 m.(.approx)
palku1:
real ans us. 3÷8×20=15m
this is wrong.....my answer is correct....see its height 6÷8=3÷4
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