At a charity benefit with 22 people in attendance, three $50 gift certificates are given away as door prizes. Assuming no person receives more than one prize, in how many different ways can the gift certificates be awarded?
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In the Isosceles Triangle ABC,
∠BAC = 30°
So,
∠CBA also = 30° = x (Opposite side in a Isosceles ∆)
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If ∠BAC & ∠CBA = 30°
Then,
∠BAC + ∠CBA + ∠ACB = 180° (Angle Sum Prop. of a Triangle)
➠ 30° + 30° + ∠ACB = 180°
➠ ∠ACB = 180° - 60°
➠ ∠ACB = 120°
If ACB = 120° Then,
∠BCD = 180° - 120°
∠BCD = z = 60°
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If z = 60°
Then,
Y also = 60° (Opp. Sides in an Isosceles ∆ )
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Overall,
x = 30°
y = 60°
z = 60°
.
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