At a constant pressure and a temperature of 280 K, the gas in a cylinder has a volume of 10.0 liters. If the volume of the gas is increased to 20.0 liters, what is the new temperature?
A. 560 K
B. 28 K
C. 2,800 K
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a.560 is right answer
in 10 L=280k
in 1 L=280/10=28k
in 20 L=28×20=560k
in 10 L=280k
in 1 L=280/10=28k
in 20 L=28×20=560k
straysheep:
It's correct! Thank you so much!
all right and thanks for opportunity
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