Question

At a constant temperature, a gas is at a pressure of 1080 mm Hg. If the volume is decreased to 40%, find the new pressure of the gas.​

Answer 1

Answer:

P 1V1=P2V2

we know that volume has decreased by 40%, thus the volume left was 60% of initial volume

1080 × x=P2 × 0.6x

P2=1800mm of Hg

Answer 2

Ꮐiѵεɳ :

• Initial gas at press. = 1080 mm of Hg
• Volume decreased to 40%

✠[ At a constant temperature ]✠

Ƭσ Ŧiɳ∂ :

• New pressure of the gas

Տƭερ-ɓყ-Տƭερ εxρℓαɳαƭiσɳ:

Let the initial volume be “ Ꮩ ”

Here,

➟P1 = Initial pres. of the gas = 1080 mm of Hg

➟V1 = Initial vol. of the gas = V

➟V2 = Final vol. of the gas = 0.4 V

Plugging the values in the formula,

⇾1080 × V = P2 × 0.4 V

⇾ 1080 / P2 = 0.4 V/V

⇾ 1080 / P2 = 0.4

⇾ P2 = 1080 / 0.4

⇾ P2 = 10800 / 4

Aɳsωεɾ :

➨P2 = 2700 mm of Hg