Question

At a constant temperature a gas is initially at 2atm pressure.to compress it to 1/8th of its initial volume, pressure to be applied is

Answer 1

Answer:-

Given:

Initial Pressure = 2 atm.

Let Initial Volume = V

Final Volume = 1/8* Initial Volume = V/8.

We know that,

Boyle's law of gases states that at constant temperature, the Volume of a given mass of a gas is inversely proportional to the Pressure.

$→ P\: \: \alpha \:\: \frac{1}{V}$

(or)

P*V = K (Constant)

(or)

Initial Pressure* Initial Volume = Final Pressure* Final Volume.

→ (2)(V) = (V/8)*Final Pressure

→ 2V * 8/V = Final Pressure.

→ Final Pressure = 16 atm.

Hence, the Pressure to be applied is 16 atm.