Chemistry, asked by khanicharsadda34, 6 months ago

At a constant temperature, an ideal gas is compressed from 6.0 liters to 4.0 liters by a constant external pressure of 5.0 atm. How much work is done on the gas? solve it PlZz urgent​

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Answered by plb62
11

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Answered by qwmagpies
4

Work done by the gas is 1013J.

Given: At a constant temperature, an ideal gas is compressed from 6.0 litres to 4.0 litres by the constant external pressure of 5.0 atm.

To find: We have to find the work done.

Solution:

The work done of an ideal gas is given as-

W=-pdv

Where p is the external pressure.

dv will be given as-

dv=(v_2-v_1)

v2=4 litre

v1=6 litre

p=5atm.

Thus putting these values in the above equation we get-

w =  - 5 \times (4 - 6) \\ w =  - 5 \times  - 2 \\ w = 10

Work done on the gas is 10l.atm.

1 l.atm is equal to 101.3 Jule.

Thus 10l.atm will be equal to

101.3 \times 10 = 1013

Work done by the gas is 1013J.

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