at a constant temperature an ideal gas is compressed from 6.0 liters by a constant external pressure of 5.0 atm. how much work is done on the gas
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Explanation:
V1=6L
V2=0L
w=5(0-6)Latm
= -5×6Latm
=30Latm
=30×101.325J
=3039.75J (Ans.)
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