Question

At a construction site a pipe wrench, initially at rest at a height of 5 meters was dropped and struck the ground. a. What was the velocity (in m/s) when it hit the ground?

Answer 1

Answer:

$\bigstar{\bold{Final\:velocity=10\:m/s}}$

Explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Initial velocity(u) = 0 m/s
• Height/Distance (s) = 5 m
• Acceleration due to gravity (g) = 9.8 m/s²

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• Final velocity (v)

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ We have to fid the velocity when the body hits the ground.

→ By the third equation of motion,

  v² - u² = 2as

→ Substituting the datas, we get the value of v

   v² - 0² = 2 × 9.8 × 5

   v² = 98

   v = √98

   v = 10 m/s

→ Hence the final velocity of the body is 10 m/s

$\boxed{\bold{Final\:velocity=10\:m/s}}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ The three equations of motion are:

• v = u + at
• s = ut + 1/2 × a × t²
• v² - u² = 2as