Question

At a convention of monsters, 2/5 have no horns, 1/7 have one horn, 1/3 have two horns, and the remaining 26 have three or more horns. How many monsters a

Answer 1

let's assume that the total monsters are "M"

Now, according to the question
M-[(2M/5)+(M/7)+(M/3)]=26
M-[(42+15+35)/105]M =26
M[1-(92/105)]=26
M(13/105) = 26
M = (26x105)/13
M = 210

So there are 210 monsters in total.

Answer 2

Answer:

Let monsters attending the convention be x

x=210