At a distance 5cm and 10cm from the surface of a sphere potential are 600V and 420V find the potential over its surface
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At the distance of 5 cm and 10 cm from surface of a uniformly charged solid sphere, the potentials are 100 V and 75 V respectively. Then
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December 20, 2019avatar
Novin Chandrasekaran
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ANSWER
Let R= radius of sphere and q= charge on sphere.
here, 100=
R+0.05
kq
⇒100R+5=kq...(1) and
75=
R+0.1
kq
⇒75R+7.5=kq...(2)
from (1) and (2), 75R+7.5=100R+5
or 25R=2.5⇒R=0.1m
using (1), kq=100(0.1)+5=10+5=15
V
surface
=
R
kq
=15/0.1=150V
Charge, q=15/k=
9×10
9
15
=50/3×10
−10
C where k=1/4πϵ
0
E
surface
=
R
2
kq
=
(0.1)
2
15
=1500V/m
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